oneshot
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defmodule Rsh26pool.Voting.Hungarian do
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@moduledoc """
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Solves the assignment problem — a minimum-cost perfect matching in a weighted
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bipartite graph — with the Hungarian (Kuhn–Munkres) algorithm in O(n^3).
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This is the algorithm the proposal calls for when placing members into groups
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in grouping mode: given a cost of assigning each member to each group slot, it
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finds the assignment with the lowest total cost.
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`min_cost_assignment/1` takes an `n x m` cost matrix (a list of `n` rows, each
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a list of `m` numbers) with `n <= m`, and returns `{total_cost, assignment}`
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where `assignment` is a list of length `n` and `Enum.at(assignment, i)` is the
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0-based column matched to row `i`.
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"""
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@inf 1_000_000_000
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@spec min_cost_assignment([[number()]]) :: {number(), [non_neg_integer()]}
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def min_cost_assignment([]), do: {0, []}
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def min_cost_assignment(cost) when is_list(cost) do
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n = length(cost)
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m = length(hd(cost))
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if n > m do
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raise ArgumentError, "cost matrix must have rows <= cols (got #{n} x #{m})"
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end
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# 1-indexed access into an immutable tuple-of-tuples.
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c = cost |> Enum.map(&List.to_tuple/1) |> List.to_tuple()
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cost_at = fn i, j -> c |> elem(i - 1) |> elem(j - 1) end
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u = fill(n + 1, 0)
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v = fill(m + 1, 0)
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p = fill(m + 1, 0)
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way = fill(m + 1, 0)
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{_u, _v, p, _way} =
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Enum.reduce(1..n, {u, v, p, way}, fn i, {u, v, p, way} ->
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phase(i, m, cost_at, u, v, p, way)
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end)
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# p[j] holds the row matched to column j; invert to get column-per-row.
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row_to_col =
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Enum.reduce(1..m, %{}, fn j, acc ->
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row = elem(p, j)
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if row >= 1 and row <= n, do: Map.put(acc, row, j - 1), else: acc
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end)
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assignment = Enum.map(1..n, &Map.fetch!(row_to_col, &1))
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total =
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assignment
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|> Enum.with_index(1)
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|> Enum.reduce(0, fn {col0, i}, sum -> sum + cost_at.(i, col0 + 1) end)
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{total, assignment}
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end
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# Augmenting phase for row `i` (see the classic e-maxx Hungarian description).
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defp phase(i, m, cost_at, u, v, p, way) do
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p = put_elem(p, 0, i)
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minv = fill(m + 1, @inf)
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used = fill(m + 1, false)
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walk(0, m, cost_at, u, v, p, way, minv, used)
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end
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defp walk(j0, m, cost_at, u, v, p, way, minv, used) do
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used = put_elem(used, j0, true)
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i0 = elem(p, j0)
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ui0 = elem(u, i0)
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{delta, j1, minv, way} =
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Enum.reduce(1..m, {@inf, -1, minv, way}, fn j, {delta, j1, minv, way} ->
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if elem(used, j) do
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{delta, j1, minv, way}
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else
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cur = cost_at.(i0, j) - ui0 - elem(v, j)
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{minv, way} =
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if cur < elem(minv, j),
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do: {put_elem(minv, j, cur), put_elem(way, j, j0)},
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else: {minv, way}
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mvj = elem(minv, j)
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if mvj < delta, do: {mvj, j, minv, way}, else: {delta, j1, minv, way}
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end
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end)
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{u, v, minv} =
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Enum.reduce(0..m, {u, v, minv}, fn j, {u, v, minv} ->
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if elem(used, j) do
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pj = elem(p, j)
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{put_elem(u, pj, elem(u, pj) + delta), put_elem(v, j, elem(v, j) - delta), minv}
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else
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{u, v, put_elem(minv, j, elem(minv, j) - delta)}
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end
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end)
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if elem(p, j1) == 0 do
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{u, v, reconstruct(j1, p, way), way}
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else
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walk(j1, m, cost_at, u, v, p, way, minv, used)
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end
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end
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defp reconstruct(j0, p, way) do
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j1 = elem(way, j0)
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p = put_elem(p, j0, elem(p, j1))
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if j1 == 0, do: p, else: reconstruct(j1, p, way)
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end
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defp fill(size, value), do: value |> List.duplicate(size) |> List.to_tuple()
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end
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